What is the integral of a cumulative distribution function?
2019年2月27日 · I cannot find what is the integral of a cumulative distribution function $$\\int G(\\xi)d\\xi$$ I think it should be simple, but I have no idea where else to look for it.
Newest 'integration' Questions - Mathematics Stack Exchange
For questions about the properties of integrals. Use in conjunction with (indefinite-integral), (definite-integral), (improper-integrals) or another tag(s) that describe the type of integral being considered. This tag often goes along with the (calculus) tag.
What is an integral number? - Mathematics Stack Exchange
2020年10月31日 · In normal use, integral length would be equal to some integer, while unit length would be of length $1$ (see "unit number" here). Presumably the author meant, "in the unit ( with a different meaning! ) we use to measure lengths, these lengths are integer-valued".
What is the integral of - Mathematics Stack Exchange
2017年10月12日 · This integral is one I can't solve. I have been trying to do it for the last two days, but can't get success. I can't do it by parts because the new integral thus formed will be even more difficult to solve. I can't find out any substitution that I can make in this integral to make it simpler. Please help me solve it.
calculus - Is there really no way to integrate $e^{-x^2 ...
$\begingroup$ @user599310, I am going to attempt some pseudo math to show it: $$ I^2 = \int e^-x^2 dx \times \int e^-x^2 dx = Area \times Area = Area^2$$ We can replace one x, with a dummy variable, move the dummy copy into the first integral to get a double integral.
calculus - relation between integral and summation - Mathematics …
2012年8月21日 · Well, the linearity just follows from the fact that you can swap integral and the sum (i.e. these two operators commute) - but an extremely important fact that the sum is a special case of an integral, and the integral is a limit of sums is not used there.
solving the integral of $e^{x^2}$ - Mathematics Stack Exchange
The integral which you describe has no closed form which is to say that it cannot be expressed in elementary functions. For example, you can express $\int x^2 \mathrm{d}x$ in elementary functions such as $\frac{x^3}{3} +C$. However, the indefinite integral from $(-\infty,\infty)$ does exist and it is $\sqrt{\pi}$ so explicitly:
Lebesgue integral basics - Mathematics Stack Exchange
The Riemann integral is like picking up the coins, one-by-one, and adding the denomination of each to a running total. The Lebesgue integral is like sorting the coins by denomination first, and then getting the total by multiplying each denomination by how many you have of that denomination and then adding up those numbers.
Turning infinite sum into integral - Mathematics Stack Exchange
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Does the complex conjugate of an integral equal the integral of …
$\begingroup$ @Karlo, Essentially that is because integral is 'sum of infinitesimals' so that we can distribute conjugate to each summand. Of course, the precise justification depends on how we define integral.