Taylor Series Expansion of $\\tanh x$ - Mathematics Stack Exchange
2014年12月5日 · An easy way to compute the coefficients of the Taylor series of $\tanh$ is to consider that: $$\cosh(z)=\prod_{n=0}^{+\infty}\left(1+\frac{4z^2}{(2n+1)^2 \pi^2}\right ...
machine learning - Why is tanh almost always better than sigmoid …
2018年2月26日 · @elkout says "The real reason that tanh is preferred compared to sigmoid (...) is that the derivatives of the tanh are larger than the derivatives of the sigmoid." I think this is a non-issue. I never seen this being a problem in the literature. If it bothers you that one derivative is smaller than another, you can just scale it.
$n$th derivative of $\\tanh$ - Mathematics Stack Exchange
2018年1月29日 · Derivative polynomial of the hyperbolic tangent function. It is known that $$ \tan z=\operatorname{i}\tanh(\operatorname{i}z). $$ So, from the derivative polynomial of the tangent function $\tan z$, we can derive the derivative polynomial of …
pronunciation of sinh x, cosh x, tanh x for short [closed]
My maths professor Siegfried Goeldner who got his PhD in mathematics at the Courant Institute at New York University under one of the German refugees from Goetingen, in 1960, pronounced sinh as /ʃaɪn/, cosh as /kɒʃ/ ("cosh") and tanh as /θæn/, i.e., as shine, cosh and than with a soft th like in theta---the same pronunciation in three countries, in three continents, but 53 years ago.
machine learning - tanh activation function vs sigmoid activation ...
Having stronger gradients: since data is centered around 0, the derivatives are higher. To see this, calculate the derivative of the tanh function and notice that its range (output values) is [0,1]. The range of the tanh function is [-1,1] and that of the sigmoid function is …
Rapid approximation of $\\tanh(x)$ - Mathematics Stack Exchange
Assuming the numbers are stored in fixed point with an 8 bit fractional part then the approximation to $\tanh(x)$ should work to the limit implied by the resolution, or for arguments $\tanh^{-1}(\pm[1 - \frac{1}{2^8}]) \approx \pm3.1$.
calculus - Converting $\tanh^{-1}{x}$ to an expression involving …
Set $ y = \tanh^{-1} t $ and take $\tanh$ to take both sides so we have $$ \tanh y = t .$$
How do I derive the Maclaurin series for $\\tanh(x)$?
2015年6月3日 · $\begingroup$ Neither is a Maclaurin series, which has to look like $\sum a_n x^n$. You can do a formal division, and obtain after some pain a few terms.
Find the first three terms of the maclaurin series of $\\tanh(z)$ and ...
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Finding infinite limit of hyperbolic trig functions
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