【発展】直角三角形の面積とsin2θ | なかけんの数学ノート

The dimensions of a rectangular duct are to be chosen so that the duct has the maximum cross-sectional area when placed in the opening of a right triangle.Area of the shaded rectangle (Objective function):y = hw^0.7(0.5 - w^0.5)Constraint:Determine the optimal values of h and w using the method of Lagrange multipliers for constrained optimization.0.7m

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